$-4\:+\:6\left(-4x\:+\:3\right)$
$\left(21x^2-4y\right)\left(6x^2+y\right)$
$\frac{\left(-p^0m\right)^3}{3p}$
$y'+y\:\tan\left(x\right)=0$
$\lim_{x\to2}\left(\frac{2x^2-3x-2}{x^2-x-1}\right)$
$y^3+y^6-y^5$
$2\cot\left(2\alpha\right)=\cot\alpha-\tan\alpha$
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