$3x+11\le6\left(x+8\right)$
$\frac{dy}{dx}-4y=e^{4x}$
$\sqrt{320x^5}$
$\frac{2x^3-11}{x^2+8x+15}$
$-2x^2-4x-5-4x^2+3x+-1$
$160\pi+120\pi^3$
$\frac{d}{dx}\left(2^{-3x^4}tan\left(y^5\right)=e^{x^2}ln\left(1+x^6\right)\right)$
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