$4x\left(\sin^2\left(x\right)-\cos\left(3x\right)\right)$
$y=3\tan\pi x^2$
$7x-5>14x-2y$
$\left(m^{a-1bx}+\frac{1}{2}y^3\right)\cdot\left(m^ab^{x-1}\right)$
$x^2+36x-2040=0$
$\left(12^4\right)^{\:-5}$
$\left(2x^2-7\right)\left(2x^2-6\right)$
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