$\left(10x^3-9y^5\right)^2$
$\cos\:\left(-u\right)=\cos\:\left(u\right)$
$1+\cos\left(x\right)-\sin^2\left(x\right)$
$\lim_{x\to-2}\frac{\left(x+2\right)}{x^4-16}^2$
$x^2+\sqrt[3]{a}x+\sqrt[3]{a^2}$
$\frac{160x^{-3}y^2}{-40x^2y}$
$\lim_{h\to0}\left(\frac{\sin\:\left(a+h\right)-\sin\:\left(a\right)}{h}\right)$
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