$5-7+10-4+1-3-6+2-1$
$-7\cdot9+4\cdot10$
$\left(5st\right)\left(-7r\right)$
$\left(\frac{8a^3b^4}{-4ab^4}\right)$
$\left(2x-5y\right)\left(4x-3y\right)$
$\int\left(x+1\right)^{12}dx$
$\sqrt[2]{b}\cdot\sqrt[4]{b^3}$
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