$\left(2x-4y\right)^2-3\left(x^2+y\right)$
$10x^2+4x+6$
$\left(5x+2\right)\left(3x-1\right)$
$13-\left|15-\left(6-8\right)+\left(5-9\right)\right|$
$\int\frac{sec^2\left(x\right)tan^2\left(x\right)}{\sqrt{9-tan^2\left(x\right)}}dx$
$-16\cdot n=256$
$7\left(4x-2\right)$
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