$\lim_{x\to0}\left(\frac{e^2-1}{x^2+2x}\right)$
$\left(\sec^{2}\alpha-\tan^{2}\alpha\right)$
$\int\frac{x^2+6}{\left(x+1\right)^2\left(x-2\right)}dx$
$x^2+18x+32$
$\left(-3.\:6\right)-\:-10$
$y'+y=-2$
$\frac{dy}{dx}=\frac{1}{e^{3x}\left(4-\sqrt{y}\right)}$
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