$\int_{\infty}^{11}\left(\frac{x}{x^2-4}\right)dx$
$-3x^{-4}$
$\int\:\frac{\left(u+3\right)^2}{u}du$
$\left(x-6\right)\left(x-2\right)\left(x-3\right)$
$\frac{1}{\sqrt{x-1}+\sqrt{x+1}}$
$2x+5=x+2$
$\frac{98.07}{58.31}\cdot5,88$
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