$\frac{dy}{dx}+4y=\frac{\sqrt{2}}{3}\left(1-\sqrt{2}\right)e^{-x}$
$3x^2-6x+2=0$
$\frac{-14x^4y^7}{6x^5y^2}$
$\int e^{\frac{x}{7}}dx$
$f\left(x\right)=0.23\ln\left(1\right)+0.46$
$\int35tan^5\left(x\right)sec^4\left(x\right)dx$
$\frac{d}{dx}\:2y^2+xy+x^2=1\:$
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