$\left(2x^2+4x\right)\left(2x^2+4x\right)$
$x+3y+8+7x-2y-5$
$x-y+3z=1$
$\lim\:_{x\to\:0}\left(x\left(lnx\right)^3\right)$
$4n+3<6n+8-2n$
$2^{2x}+2\cdot2^x-3=0$
$10x^2+x-21$
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