$\left(\frac{2x^2}{5y^4}\right)^{-2}$

$\int\left(\frac{\sec\left(x\right)^2}{\tan\left(x\right)^2+13\cdot\tan\left(x\right)+42}\right)dx$

$2\cdot\left(-10\right)\cdot4$

$\left(3x^2+y^2\right)\left(9x^4-3x^2y^2+y^4\right)$

$2y\:+\:5\:-\:4y\:-\:4$

$48x^3-36x^2$

$\frac{126}{-63}$