$\sqrt[4]{a^2n+1}\sqrt[4]{a-1}$
$3\cdot\left(4+6\right)$
$-2x^3\:-x^2\:-3x\:-6:\:\left(x\:+1\right)$
$\frac{2x^2+5x-18}{x+4}$
$\frac{5^{12}}{5^1}.\frac{5^8}{5^9}$
$64\cdot17$
$\lim_{n\to\infty}\left(\frac{2^n+\sqrt{3}}{4^n}\right)$
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