$\frac{1}{4}-\left(\cos^2\frac{\pi}{12}-\sin^2\frac{\pi}{12}\right)$

$125y^9+\:216z^{12}$

$\frac{3}{4}m^3-\frac{1}{2}m^2n+\frac{2}{5}mn^2-\frac{1}{4}por\:\frac{2}{3}m^2+\frac{5}{2}n^2-\frac{2}{3}mn$

$\:x\::\:\left(-3\right)\:+\:2\:<=\:4$

$\cos2\left(x\right)-3\sin^2\left(x\right)=0$

$x^8-1\:sobre\:1\:+\:x^4$

$0=-4x+x^2+4$