$\left(6x^3-2\right)^3$
$\left(6q^6\right)^3$
$\lim_{x\to\infty}\left(\frac{2x^2+1}{x^2+x}\right)$
$\left(\left(-3\right)\sqrt{2}-\left(1\right)\sqrt{2}\right)$
$x^2+x=12$
$25x^2+100x+100$
$x^3-2x^2-3x+1x=-1$
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