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Exercise

$3\left(3x-2\right)>\left(x+4\right)\left(4-x\right)$

Step-by-step Solution

1

Wenden Sie die Formel an: $\left(a+b\right)\left(a+c\right)$$=a^2-b^2$, wobei $a=4$, $b=x$, $c=-x$, $a+c=x+4$ und $a+b=4-x$

$3\left(3x-2\right)>16-x^2$

Final answer to the exercise

$3\left(3x-2\right)>16-x^2$

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