$\lim_{x\to4}\left(\frac{3-x}{x^2-16}\right)$
$\lim_{x\to0}\frac{\left(4x-3x\right)}{x}$
$3+5-\left(4-6\right)-7$
$2x\:-4\left(10\:x\:-5\right)$
$\left(-9\right)\left(-8\right)\left(-7\right)\left(-6\right)\left(+5-3-2\right)$
$\left(\frac{\left(-1\right)^{n+1}}{3^{n+1}}\right)\left(x-4\right)^n$
$\int\frac{4}{\left(x^4-1\right)}dx$
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