$\frac{\log_b\left(32\right)}{\log_b\left(2\right)}$
$\frac{x}{1.9}=-4.7$
$\tan\left(5x\right)^2=1$
$\frac{x^2-1}{x}$
$\lim_{x\to0}\left(\frac{3x^2+2x-1}{2x^2-x+1}\right)$
$\frac{2b}{3}+23+\frac{8b-5}{5}=90$
$\frac{3x^2}{2x^5}$
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