$\left(-\frac{3}{5}\:x^3\right)\left(\frac{2}{4\:}\:x^2\right)$
$6b-5=1$
$\left(-13\right)\cdot\left(-11\right)$
$2x^2\:+\:12x\:-\:16\:=0$
$-\left(tx^{-3}\right)+\left(tx^{-1}\right)$
$\left(x^{2+xy\:+y^2}\right)\left(x-y\right)$
$5+3\cdot\left(-2\right)-\left(-7+3\right)$
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