$\lim_{x\to0}\left(\frac{x^2}{x+2}\right)$

$cos\left(-t\right)=\cos\left(t\right)$

$\frac{d}{dx}\left(\ln\left(xy\right)-\sqrt{x}+\sqrt[5]{y}=8\right)$

$y^'=lnx$

$2y^2+5y+2=0$

$\int_1^2\frac{e^{\frac{-1}{x}}}{x^2}dx$

$\lim_{x\to0}\left(\frac{\cos\left(x\right)-1+\frac{1}{2}x^2}{8x^4}\right)$