$\int\left(\frac{-6x^3-8x^2-3x+9}{x}\right)dx$
$36a-16$
$\frac{dy}{dx}=\left(2x-5y+2\right)$
$\left(4x^2\right)\cdot\left(2x\right)+\left(25\right)$
$-24x+3x^3-6x^2$
$a^2+10ab+25b^2$
$\frac{dy}{dx}\sqrt[4]{1.6x^2+1.3}$
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