$2\frac{dy}{dx}=x^2$
$\tan\left(x\right)\tan\left(x-y\right)=1$
$\frac{2^{-8}.3^5.5^{-6}}{2^{-7}.3^6.5^{-5}}$
$=\cos2x-1$
$cos\left(3x+4x\right)$
$2\left|27+\left(x+y\right)\right|=2\left|\left(y+27\right)+x\right|$
$\frac{dy}{dx}=c\cdot\ln\left(x\right)+c$
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