$\frac{d}{dx}\left(2x^3-3xy+y=5\right)$

$2\left(\frac{x+1}{x-1}\right)$

$y^3+4y^2-5y$

$a^2-2ab\:$

$\frac{dq}{dp}\left(q^3=\left(p-2^{\frac{1}{2}}\right)\left(p^2+1\right)\left(p^4+6\right)\right)$

$3x+\frac{1}{2}<7x+\frac{5}{2}$

$\frac{6\cdot z}{5}\cdot\frac{\cdot z}{5}$