$x^2+4x\:=\:20$
$z^2+5x^2+5z^2$
$2xydx+x^2-1dy=0$
$4\left(-x-3\right)-3\left(x+9\right)+27$
$\sqrt{x}\left(x-1\right)$
$\frac{dy}{dx}=\frac{x-y+1}{x-y-1}$
$\left(2y^2-2\cdot\:\left(\frac{0}{2}\right)y+\left(\frac{0}{2}\right)^2\right)$
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