$2a+8b-6c$
$\sin\left(x\right)-\:\left(\sin\left(x\right)\cos^2\left(x\right)\right)=\sin^3\left(x\right)$
$2x^2+8x-12=0$
$\frac{2^2+2z-3}{z+3}$
$\frac{dy}{dx}=\frac{\left(4x-2\right)\left(y^2+2y-3\right)}{x^3-x^2-2x}$
$2x^2-x^2+8x$
$-6c^8d^{-3}g^{-\frac{4}{3}}$
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