$\frac{3x}{x\:+\:5}\:+\:\frac{x\:+\:5}{3x}$
$\frac{\left(sec\:a\:-\:tana\right)}{seca\:+\:tan\:a}$
$-2\cdot7^2+12\cdot7-10$
$\left(\frac{1}{2x}\right)^2$
$6x^2+y^2=9$
$\frac{x}{4}-1>5$
$12x+8=20$
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