$3x-5=16$
$4x^2+12x+10=0$
$g\left(x\right)\:=4x^2\left(3x^5\right)$
$-9\times7\times2$
$\lim_{x\to125}\left(\frac{125-25\sqrt[3]{x}}{2x\left(x-125\right)}\right)$
$3c^4\cdot9c^6\cdot81c^{-4}$
$\frac { x ^ { 4 } - 4 x ^ { 2 } + 6 } { x + 2 }$
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