$\frac{2x-8}{4}\ge2x-5$
$7\left(2x-1\right)-8=-3\left(x+5\right)$
$\frac{-2x^3+7x^2+9x}{x}$
$\frac{d}{dx}\frac{29}{\sqrt[4]{x}}$
$\frac{1-n^5}{1-n}$
$\frac{64-x^{12}}{8+x^2}$
$2x^2+x+3x^3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!