$\lim_{x\to\infty}\left(\sqrt[x]{4^{3x+1}}\right)$

$\:\left(2x^2-5y^4\right)^3\:$

$=12m^{3}-2m^{2}n$

$2a+3\left(4a-1\right)$

$-\frac{1}{2}v-1>\frac{3}{8}+\frac{5}{6}$

$6x+3y=15$

$\frac{\left(\csc\:^2\left(x\right).\cot\:\left(x\right)-\cot\:^3\left(x\right)+\sec\:\left(x\right)-\cot\:\left(x\right)\right)}{\csc\left(x\right)}$