$y^''+\:24y'+4y=0$
$20x\:4x\:2x\:1x\:32x\:\left(4\right)^2\:\left(1\right)^3$
$-x+2>0$
$\frac{x-2}{x+3}>=2$
$\left(3x-\sqrt{3}\right)\left(3x+\sqrt{3}\right)$
$\frac{x-10}{x^24x+2}$
$x^2+3x-72=0$
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