$tan\left(t\right)\left(5cos\left(t\right)-5csc\left(t\right)\right)$

$x\left(\sqrt{x+25}+5\right)$

$\left(z^4+2y^3\right)^2$

$sin^2x=\frac{sec^2x-1}{1+tan^2x}$

$\int\frac{1}{\left(x^2+3x+2\right)\left(x-3\right)}dx$

$\left(4+x\right)\left(\frac{dy}{dx}\right)=3+y$

$-18\cdot72$