$\sqrt[3]{26+25.9815}+\left(26-15\cdot\:\sqrt{3}\right)^{\frac{1}{3}}$

$-3\left(7-5x\right)$

$\left(4x^3-5x^2-x-6\right)\left(2x^2-3x+4-5x^3\right)$

$\frac{z^2-5z-14}{z-7}$

$\int_0^{\infty}\left(\frac{13x}{16+x^2}\right)dx$

$6ab^2c^3+18a^2b^2c^2-12a^3b^4$

$f\left(x\right)=\left(3\right)^2$