$\left(1.2a-4b\right)^2$
$\lim_{x\to\infty}\left(\frac{\left(2n^2+6\left(2^n\right)\right)}{\left(3\left(2^n\right)-n^2+1\right)}\right)$
$x^2-10x=144$
$3x+2\left(2x-4\right)$
$\frac{dy}{dx}-\frac{3x^2}{2y}=0$
$\left(x^2+1\right)y'=x\left(y^3+y\right)$
$25x^2-x+9$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!