$\lim_{x\to-3}\:2x^{\frac{1}{x+3}}$
$4x^2=16x$
$\lim_{x\to0}\left(\frac{1}{x}-\frac{1}{2e^x-2}\right)$
$x\frac{dy}{dx}+3y=x^2$
$\left(6x-2\right)\left(4x-3\right)\:$
$\lim_{x\to\infty}\left(\frac{3x}{2+3x}\right)^{\left(x\right)}$
$12x^2+60x-75$
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