$\lim_{x\to\infty}xe^{\frac{6}{x}}-x$
$\frac{x+1}{x-1}=\frac{3x+3}{x}$
$x^2-3x^2-5x^2$
$10x^3+8x+12$
$\left(-10c-7\right)\left(-10c-11\right)$
$\int\:4xe\:^{-x}dx$
$2x^4+5x^3-x-6$
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