$y'=y^4$
$\frac{dy}{dx}=1+y+x^2+yx^2$
$\ln\left(1-3y\right)^{\frac{1}{3}}=\frac{x^3}{3}$
$\left(5y+2x\right)\left(5y-9x\right)$
$200+2.33\cdot50$
$\left(-4xy^4\right)^4$
$11x+6<35$
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