$\ln\left(3.280\:x\:10^2\right)^{\frac{2}{5}}$

$\left(\frac{1}{x}-y\right)\left(\frac{1}{x^2}+\frac{y}{x}+y^2\right)$

$4x^4\cdot2x^{-3}$

$\left(x\:-3\right)\left(x\:+\:6\right)\left(x\:+\:i\right)$

$\left(\frac{y}{x}-\frac{x^2}{y}\right)^2$

$-35+-3+-38$

$\sqrt[4]{16x^8y^9}$