$\lim_{x\to0}\left(\frac{8x^2}{96x^5-3}\right)$
$4\times\left(-2\right)\times\left(-5\right)\times\left(-11\right)\times5$
$2x^2-14x+32$
$10=00$
$8x+3x+2x-4x$
$a^4-a^2b^2$
$\frac{x}{x+1}\:+\frac{2x}{x+1}$
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