$3x\ge-\frac{2}{3}$
$\frac{dy}{dx}=\frac{x+y^2x}{y}$
$2-\left(-8\right)\cdot\left(\left(-3\right)+7\right)$
$c^2-16$
$\cos\left(2x\right)-3cosx+2=0$
$\frac{3c^2d-18cd^2-6cd}{3cd}$
$10\:cm\:b\:20cm\:\sqrt{300}$
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