$1+\frac{3}{\infty^2}$
$\left(3m+2nm\right)^2$
$49t^2-9$
$\tan^2x\:+2\sec x-2$
$\int6exdx$
$\frac{x\:^2-25}{x-5}$
$\left(\tan\left(x\right)+1\right)\left(3\tan\left(x\right)-\sqrt{3}\right)=0$
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