$y^{'\:}=\frac{-\left(3y^2+1\right)x}{x^2+1}$

$\lim_{x\to\infty}\left(\frac{1}{6x+3}\right)$

$w^6-x^6$

$sec\left(arctan\:\left(x\right)\right)$

$\left(\frac{3}{4y}+\frac{1}{6}\right)\left(\frac{3}{4}y-\frac{5}{8}\right)$

$\frac{5^2.\left(-2\right)^3.\left(-1\right)^5.3^2}{3^4.\left(-5\right).2^2.\left(-1\right)}$

$2x+2\le x+4$