$3\left(n+6\right)$
$2x-8\ge\:9x-10$
$x+3\left(2x^2-x-8\right)$
$\left(+5\right)+\left(-3\right)-\left(-9\right)$
$-\left(-5+3-7+13\right)+\left(5-9\right)$
$\lim_{x\to0}\left(\frac{cos\left(4x\right)-1}{sin\left(7x\right)}\right)$
$3x^3+x^3+5x^3$
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