$\int\left(x-10\right)\cos\left(x\right)dx$
$\int\frac{1}{\left(x^2+6x+13\right)}dx$
$7x-4\left(2x-5\right)=3\left(5x-2\right)-6$
$-x^3+3x^5+4x^2-10x-8-2x-8$
$\tan\left(-\frac{9}{4}\pi\right)$
$100x+50y=2000$
$\left(3x-\frac{1}{2}x^2\right)^5$
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