$\int4e^{4x}\:cos\left(x\right)dx$
$25-9i-12+5i$
$8-9+0+3y^3-9$
$\int\frac{4-x}{x^2-4x+3}dx$
$\left(3x+4y\right)\cdot\left(2x-8y+3\right)$
$\:\:\:\:\:-45x\:-9$
$9^{-4}\cdot9^{-4}\cdot9^6$
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