$3x^2+5=18x$
$+9-17-8+9-7$
$726x^2+132x+6$
$\frac{dx}{dt}=-\frac{x^2+1}{4tx}$
$\frac{dq}{dt}=-0.5q$
$\log_{10}\left(x+3\right)+\log_{10}\left(x+6\right)=1$
$\int\left(6-3x\right)^{-6}dx$
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