$3m^2+4m-15$
$\left(a^2b^4-7\right)\left(a^2b^4+8\right)$
$\left|16\right|+\left|-5\right|$
$\frac{\left(x-3\right)}{x+5}<1$
$3+5+6+3+1$
$raices\left(x^3-5x^2-x+5\right)$
$.04a^2-.12ab+.09b^2$
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