$tangente$
$\frac{dx}{dy}=\frac{\left(2y+3\right)^2}{\left(4x+5\right)^2}$
$\left(25a^8b^6-25x^2\right)$
$\frac{dy}{dx}=\frac{-2y}{-x}$
$\sqrt{16x^3}y$
$6-5z+8-4z+1$
$7m-mn^5+8n-13m+2n$
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