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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=2$, $b=12$ and $c=13$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-12\pm \sqrt{12^2-4\cdot 2\cdot 13}}{2\cdot 2}$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 2x^2+12x+13=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=12 and c=13. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 6.324555 and -12.