$\int3x\cdot ln\left(x^2+3\right)dx$
$\left(10b-5\right)^2$
$m^4+2m^2+m$
$\frac{dy}{dx}=-0.06\cdot\sqrt{y}$
$\left(m+2\right)\left(m-15x\right)$
$\frac{4}{49x^2}-25=0$
$\int\left(10\left(q+10\right)\cdot e^{-\left(0.1q+1\right)}\right)dx$
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