$\left(\frac{1}{2}m^3-5n^4\right)^3$

$\frac{1}{\csc^2\left(x\right)\sec^2\left(x\right)}$

$\frac{x^3}{x-5}+\frac{1}{x-5}$

$3\left(-6\right)^4\:-\:3\left(-6\right)^3\:-\left(-6\right)^2\:+\:3\left(-6\right)\:-\:1\:$

$7ab+4ab-3ab$

$sin^2\left(b\right)+sin^2\left(b\right)tan^2\left(b\right)=\tan\left(b\right)^2$

$\frac{\tan\:^3x.\sin\:x}{\cos\:x}\:\:\:\:\:\:$