$\lim_{x\to0}\left(\frac{1-\cos\:\left(x\right)^2}{4x}\right)$

$-5+x^4=2x^2-3x^3+3x\:+x^3-3x^2-5$

$\frac{2\csc\left(2y\right)}{\csc^2\left(y\right)}$

$\frac{5^4}{5}+4$

$\frac{d^2}{dx^2}\left(2x-3y+5\right)$

$4p-10p+25$

$\lim_{x\to\infty}\left(\frac{6x^2+3}{3x^2-x-12}\right)$