$\sqrt{\frac{1}{4}}t^2u^6$
$\sec^2\left(3x^2-6x\right)\arccot\left(5x-1\right)$
$\sqrt{25^2}$
$z\left(z+9\right)\left(z-9\right)$
$x^2-3x-8$
$x^6y^3+x^3y^6-3xy+5xy-4xy$
$x^2+17x+8$
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